(3x+5)(2x^2+4x-5)=

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Solution for (3x+5)(2x^2+4x-5)= equation: 


Simplifying
(3x + 5)(2x2 + 4x + -5) = 0

Reorder the terms:
(5 + 3x)(2x2 + 4x + -5) = 0

Reorder the terms:
(5 + 3x)(-5 + 4x + 2x2) = 0

Multiply (5 + 3x) * (-5 + 4x + 2x2)
(5(-5 + 4x + 2x2) + 3x * (-5 + 4x + 2x2)) = 0
((-5 * 5 + 4x * 5 + 2x2 * 5) + 3x * (-5 + 4x + 2x2)) = 0
((-25 + 20x + 10x2) + 3x * (-5 + 4x + 2x2)) = 0
(-25 + 20x + 10x2 + (-5 * 3x + 4x * 3x + 2x2 * 3x)) = 0
(-25 + 20x + 10x2 + (-15x + 12x2 + 6x3)) = 0

Reorder the terms:
(-25 + 20x + -15x + 10x2 + 12x2 + 6x3) = 0

Combine like terms: 20x + -15x = 5x
(-25 + 5x + 10x2 + 12x2 + 6x3) = 0

Combine like terms: 10x2 + 12x2 = 22x2
(-25 + 5x + 22x2 + 6x3) = 0

Solving
-25 + 5x + 22x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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